![]() How do we get the factorial to “stop” at 3? We need to get rid of the 2 × 1. We only want 5 × 4 × 3 (the total number of options). To do this, we started with all five options then took them away one at a time (four, then three, etc.) until we ran out of ribbons.įive-factorial (written 5!) is: 5! = 5 × 4 × 3 × 2 × 1 = 120.īut 120 is too big! It would work if we had five ribbons. We had to order three people out of five. The total number of options was 5 × 4 × 3 = 60. All that matters is that we understand that we had five choices at first, then four and then three. Let’s say C wins the yellow ribbon.įor this example, we picked certain people to win, but that doesn’t really matter.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |